Python itertools module provide inbuilt permutation() method to find the permutation. Now len() is 2, hence the else branch of the if is taken. Permutations Medium 16.5K 268 Companies Given an array nums of distinct integers, return all the possible permutations. A permutation is an arrangement of a set where order does matter. > from itertools import > data 2,6,9,3 > x. This is trivial, since len(') is 1 then the first branch of the if condition is taken and the return value is itself (this complies with rule 2.1). permutations(n,r) generator returns the permutation of n by r. Now we try to 'mental execute' it in order to shed some light for the absolute beginner. Python - All combination Dictionary List - GeeksforGeeks Generate all permutations of a List in Python - thisPointer TheAlgorithms-Python/heapsalgorithm.py. The program is a straightforward (possibly inefficient, see the remarks at the bottom of the page) implementation of the recursive algorithm. Trying to Understand the Code by 'Mental Execution' The number of permutations on a set of n elements is given by n. Such code is not mine, it is the original snippet the OP was asking for explanations (as a matter of fact, I am more inclined towards Lua than Python and I had to lookup the enumerate function in Python's documentation in order to fully understand the code). Order of arrangement of object is very important. Let’s look at an example using Python’s itertools library. In order to win it does not matter if the draw is 12345 or 54321: if you have these numbers, you won. I can do each permutation individually using: import itertools itertools.permutations(aa1,aa2,aa3,aa4,aa5) I have a few tens of lists and ideally, Id like to do them automatically.
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